lastIndexOf method

  1. @override
int lastIndexOf(
  1. I color, [
  2. int? start
])
override

The last index of element in this list.

Searches the list backwards from index start to 0.

The first time an object o is encountered so that o == element, the index of o is returned.

final notes = <String>['do', 're', 'mi', 're'];
const startIndex = 2;
final index = notes.lastIndexOf('re', startIndex); // 1

If start is not provided, this method searches from the end of the list.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('re'); // 3

Returns -1 if element is not found.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('fa'); // -1

Implementation

@override
int lastIndexOf(I color, [int? start]) {
  assert(start == null || (start >= 0 && start < length));
  return colors.lastIndexOf(color as O, start);
}