mockAll method

@Deprecated('mockAll cannot register dependencies under their interface types due to ' 'Dart type erasure. Use chained .mock<T>() calls instead.') ZenTestMode mockAll(Map<Type, dynamic> mocks)

Mock multiple dependencies at once.

⚠️ DEPRECATED — This method is broken and cannot be fixed.

Due to Dart's type erasure, calling Zen.put(instance) with a Map<Type, dynamic> value loses the generic type parameter T. The instance is always registered under dynamic instead of the intended interface type, so Zen.find<AuthService>() will return null even after mockAll({AuthService: FakeAuthService()}).

Use chained .mock<T>() calls instead:

Zen.testMode()
  .mock<AuthService>(FakeAuthService())
  .mock<ApiClient>(MockApiClient());

Implementation

@Deprecated(
  'mockAll cannot register dependencies under their interface types due to '
  'Dart type erasure. Use chained .mock<T>() calls instead.',
)
ZenTestMode mockAll(Map<Type, dynamic> mocks) {
  ZenLogger.logWarning(
    '🧪 ZenTestMode.mockAll() is broken: instances are registered under '
    '`dynamic` not the interface type. Use .mock<T>() chains instead.',
  );

  for (final entry in mocks.entries) {
    ZenLogger.logDebug('🧪 Test Mode: Mocking ${entry.key}');
    // BUG: Dart infers T=dynamic here, not entry.key.
    // This registers under `dynamic`, making find<T>() always return null.
    final instance = entry.value;
    Zen.put(instance);
  }

  return this;
}