truckRouteSearchPage static method

Future<void> truckRouteSearchPage({ required List<LatLng> wayPoints, int? drivingMode, TruckInfo? truckInfo, int? showFields, RouteResultBack? back, })

最多支持6个途经点，8个一页

Implementation

static Future<void> truckRouteSearchPage({
  required List<LatLng> wayPoints,
  int? drivingMode,
  TruckInfo? truckInfo,
  int? showFields,//ShowFields.
  RouteResultBack? back,
}) async {
  if(wayPoints.length<2) return;
  int pageLimit = 7; // 最大6个途经点即8个点，预留上一个连接点，正好每页7个
  //int totalPage = wayPoints.length % pageLimit;//总页数
  //需要采集的数据，分页只返回一條綫路
  List<String> polylineList = [];
  num distance = 0;
  num duration = 0;
  //开始分页采集
  nextPage(page,limit) async {
    List<LatLng> pagePoints = paging<LatLng>(wayPoints, page, pageLimit);
    if(pagePoints.isEmpty){
      if(back!=null) back(1000,RouteResult(paths: [Path(polyline:polylineList.join(";"),distance: distance,duration: duration)]));
      return;
    }
    if(page>1) pagePoints.insert(0,pagingLast<LatLng>(wayPoints, page-1, pageLimit));//加入上一页的最后一个点，插在首位
    await truckRouteSearch(wayPoints:pagePoints,drivingMode:drivingMode,showFields:showFields,truckInfo:truckInfo, back:(int? code, RouteResult data){
      if(code != 1000) {
        if(back!=null) back(code,data);//只要有一页报错，线路中断，就不要继续了
        return;
      }
      if(data.paths==null || data.paths!.isEmpty) {
        nextPage(page+1, pageLimit);
        return;
      }
      List<String>? pointStr = data.paths?[0].polyline?.split(";");
      if(pointStr!=null) polylineList.addAll(pointStr);
      duration += data.paths?[0].duration??0;
      distance += data.paths?[0].distance??0;
      nextPage(page+1, pageLimit);
    });
  }
  nextPage(1,pageLimit);
}