init method
Creates a copy of this using the provided name
for late initialization.
If $name was already set, it should have precedence over name
.
Example: Arg(0).init(name: 'integer') => Arg(0, name: 'integer') Arg(0, name: 'int').init(name: 'integer') => Arg(0, name: 'int')
Implementation
@override
ConstArg<T> init({required String name}) => this;