sendError method

Future<void> sendError(int id, String topic, String method, JsonRpcError error, { EncodeOptions? encodeOptions, })

Implementation

Future<void> sendError(
  int id,
  String topic,
  String method,
  JsonRpcError error, {
  EncodeOptions? encodeOptions,
}) async {
  final Map<String, dynamic> payload = JsonRpcUtils.formatJsonRpcError(
    id,
    error,
  );
  final String? message = await core.crypto.encode(
    topic,
    payload,
    options: encodeOptions,
  );

  if (message == null) {
    return;
  }

  final RpcOptions opts = MethodConstants.RPC_OPTS.containsKey(method)
      ? MethodConstants.RPC_OPTS[method]!['res']!
      : MethodConstants
          .RPC_OPTS[MethodConstants.UNREGISTERED_METHOD]!['res']!;
  await core.relayClient.publish(
    topic: topic,
    message: message,
    ttl: opts.ttl,
    tag: opts.tag,
  );
  // await history.resolve(payload);
}