distributeNodesHorizontally method

void distributeNodesHorizontally(List<String> nodeIds)

Distributes nodes evenly along the horizontal axis.

Requires at least 3 nodes. Sorts nodes by X position, keeps the leftmost and rightmost nodes in place, and distributes the middle nodes evenly.

Implementation

void distributeNodesHorizontally(List<String> nodeIds) {
  if (nodeIds.length < 3) return;

  final nodes = nodeIds.map((id) => _nodes[id]).whereType<Node<T>>().toList();
  if (nodes.length < 3) return;

  nodes.sort((a, b) => a.position.value.dx.compareTo(b.position.value.dx));

  final leftmost = nodes.first.position.value.dx;
  final rightmost = nodes.last.position.value.dx;
  final spacing = (rightmost - leftmost) / (nodes.length - 1);

  runInAction(() {
    for (int i = 1; i < nodes.length - 1; i++) {
      final targetX = leftmost + spacing * i;
      final newPosition = Offset(targetX, nodes[i].position.value.dy);
      nodes[i].position.value = newPosition;
      nodes[i].setVisualPosition(_config.snapToGridIfEnabled(newPosition));
    }
  });

  internalMarkNodesDirty(nodeIds);
  rebuildConnectionSegmentsForNodes(nodeIds);
}