leaveRoom method

FutureOr<int> leaveRoom()

@detail api @author luomingkang @brief 离开游戏房间。
调用此方法结束通话过程，并释放所有通话相关的资源。 @return - 0: 调用成功。如果用户是房间内可见用户，触发以下回调： - 远端用户收到 rtcRoom:onUserLeave:reason:{@link #ByteRTCGameRoomDelegate#rtcRoom:onUserLeave:reason} 回调通知。 - 正在发布的流会被取消发布。远端用户收到 rtcRoom:onVideoPublishStateChanged:info:state:reason:{@link #ByteRTCGameRoomDelegate#rtcRoom:onVideoPublishStateChanged:info:state:reason}、rtcRoom:onAudioPublishStateChanged:info:state:reason:{@link #ByteRTCGameRoomDelegate#rtcRoom:onAudioPublishStateChanged:info:state:reason}、rtcRoom:onScreenVideoPublishStateChanged:userId:state:reason:{@link #ByteRTCGameRoomDelegate#rtcRoom:onScreenVideoPublishStateChanged:userId:state:reason} 和/或 rtcRoom:onScreenAudioPublishStateChanged:userId:state:reason:{@link #ByteRTCGameRoomDelegate#rtcRoom:onScreenAudioPublishStateChanged:userId:state:reason} 回调通知。 - < 0: 调用失败，参看 ByteRTCReturnStatus{@link #ByteRTCReturnStatus} 获得更多错误说明。 @note - 加入房间后，必须调用此方法结束通话，否则无法开始下一次通话。 - 此方法是异步操作，调用返回时并没有真正退出房间。真正退出房间后，本地会收到 rtcRoom:onRoomStateChangedWithReason:withUid:state:reason:{@link #ByteRTCGameRoomDelegate#rtcRoom:onRoomStateChangedWithReason:withUid:state:reason} 回调通知。你必须在收到 rtcRoom:onRoomStateChangedWithReason:withUid:state:reason:{@link #ByteRTCGameRoomDelegate#rtcRoom:onRoomStateChangedWithReason:withUid:state:reason} 回调后，再销毁房间或引擎，或调用 joinRoom:userInfo:{@link #ByteRTCGameRoom#joinRoom:userInfo} 再次加入房间。

Implementation

FutureOr<int> leaveRoom() async {
  return await nativeCall('leaveRoom', []);
}