numericLiteral method
Implementation
Parser<Expression> numericLiteral() {
// Matches: digits optionally followed by .digits
final number = (digit().plus() & (char('.') & digit().plus()).optional())
.flatten();
return number.mapWithPosition((v, start, end) {
final value = v.contains('.') ? double.parse(v) : int.parse(v);
return Literal(value, v)..start = start..end = end;
});
}