dateFormatDDMMYYYY static method
Validate string as a date.
The str
parameter should be a string representing a date in the dd-MM-YYYY format.
Returns true
if the str
is valid, false
otherwise.
Implementation
static bool dateFormatDDMMYYYY(String str) {
String pattern =
r'/^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2])\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$/';
RegExp regExp = RegExp(pattern);
return regExp.hasMatch(str);
}