setRange method
Copies the objects of iterable
, skipping skipCount
objects first,
into the range start
, inclusive, to end
, exclusive, of the list.
List<int> list1 = [1, 2, 3, 4];
List<int> list2 = [5, 6, 7, 8, 9];
// Copies the 4th and 5th items in list2 as the 2nd and 3rd items
// of list1.
list1.setRange(1, 3, list2, 3);
list1.join(', '); // '1, 8, 9, 4'
The provided range, given by start
and end
, must be valid.
A range from start
to end
is valid if 0 <= start <= end <= len
, where
len
is this list's length
. The range starts at start
and has length
end - start
. An empty range (with end == start
) is valid.
The iterable
must have enough objects to fill the range from start
to end
after skipping skipCount
objects.
If iterable
is this list, the operation copies the elements
originally in the range from skipCount
to skipCount + (end - start)
to
the range start
to end
, even if the two ranges overlap.
If iterable
depends on this list in some other way, no guarantees are
made.
If any of iterable
's elements already exist in the list, a
DuplicateValueError will be thrown regardless of whether the list
is strict or not, unless the resulting list does not contain any duplicate
values once all values have been set.
Implementation
@override
void setRange(int start, int end, Iterable<E> iterable, [int skipCount = 0]) {
assert(start >= 0 && start <= end);
assert(end >= start && end <= length);
assert(iterable.length >= end - start);
assert(skipCount >= 0);
// Check if any of the values in [iterable] already exist in the list.
for (var value in iterable) {
if (_contains(value)) {
// If so, check whether the list will contain any duplicate values once
// every value has been set.
final result = List<E>.of(elements)
..setRange(start, end, iterable, skipCount);
if (_containsDuplicateValues(result, nullable: nullable)) {
throw DuplicateValueError(
_getDuplicateValue(result, nullable: nullable));
} else {
break;
}
}
}
return elements.setRange(start, end, iterable, skipCount);
}