setAll method

@override void setAll(int index, Iterable<E> iterable)

Overwrites objects of this with the objects of iterable, starting at position index in this list.

    List<String> list = ['a', 'b', 'c'];
    list.setAll(1, ['bee', 'sea']);
    list.join(', '); // 'a, bee, sea'

This operation does not increase the length of this.

The index must be non-negative and no greater than length.

The iterable must not have more elements than what can fit from index to length.

If iterable is based on this list, its values may change during the setAll operation.

If any of iterable's elements already exist in the list, a DuplicateValueError will be thrown regardless of whether the list is strict or not, unless the resulting list does not contain any duplicate values once all values have been set.

Implementation

@override
void setAll(int index, Iterable<E> iterable) {
  // Check if any of the values in [iterable] already exist in the list.
  for (var value in iterable) {
    if (_contains(value)) {
      // If so, check whether the list will contain any duplicate values once
      // every value has been set.
      final result = List<E>.of(elements)..setAll(index, iterable);

      if (_containsDuplicateValues(result, nullable: nullable)) {
        throw DuplicateValueError(
            _getDuplicateValue(result, nullable: nullable));
      } else {
        break;
      }
    }
  }
  elements.setAll(index, iterable);
}