fromJSON method
Deserialize a JSON object to map values to this NumberFilter
Implementation
@override
void fromJSON(dynamic json) {
if (json is! Map<String, dynamic>) {
return;
}
if (json.containsKey(FilterField.greaterEqual)) {
greaterEqual = json[FilterField.greaterEqual];
}
if (json.containsKey(FilterField.lessEqual)) {
lessEqual = json[FilterField.lessEqual];
}
if (json.containsKey(FilterField.greater)) {
greater = json[FilterField.greater];
}
if (json.containsKey(FilterField.less)) {
less = json[FilterField.less];
}
if (json.containsKey(FilterField.equal)) {
equal = json[FilterField.equal];
}
if (json.containsKey(FilterField.notEqual)) {
notEqual = json[FilterField.notEqual];
}
}