copyWith method

  1. @override
SupplierInfo copyWith({
  1. List<String>? phones,
  2. String? name,
  3. String? inn,
})
override

Создает экземпляр с заданными параметрами

Implementation

@override
SupplierInfo copyWith({
  List<String>? phones,
  String? name,
  String? inn,
}) {
  return SupplierInfo(
    phones ?? this.phones,
    name ?? this.name,
    inn ?? this.inn,
  );
}