LineStyle.fromJson constructor

LineStyle.fromJson(
  1. Object? raw
)

Implementation

factory LineStyle.fromJson(Object? raw) {
  if (raw is LineStyle) return raw;
  final json = JsonValue.map(raw) ?? const <String, dynamic>{};
  return LineStyle(
    color: JsonValue.string(json['color']),
    width: JsonValue.doubleOrNull(json['width']),
    type: JsonValue.string(json['type']),
  );
}