initialize method

Future<IntMsg> initialize(BoolPlayerMsg onlyAudio)

播放器初始化，创建共享纹理、初始化播放器

To initialize the player, you would need to create a shared texture and initialize the player. @param onlyAudio 是否是纯音频模式 if pure audio mode

Implementation

Future<IntMsg> initialize(BoolPlayerMsg onlyAudio) async {
  final String pigeonVar_channelName = 'dev.flutter.pigeon.super_player.TXFlutterVodPlayerApi.initialize$pigeonVar_messageChannelSuffix';
  final BasicMessageChannel<Object?> pigeonVar_channel = BasicMessageChannel<Object?>(
    pigeonVar_channelName,
    pigeonChannelCodec,
    binaryMessenger: pigeonVar_binaryMessenger,
  );
  final List<Object?>? pigeonVar_replyList =
      await pigeonVar_channel.send(<Object?>[onlyAudio]) as List<Object?>?;
  if (pigeonVar_replyList == null) {
    throw _createConnectionError(pigeonVar_channelName);
  } else if (pigeonVar_replyList.length > 1) {
    throw PlatformException(
      code: pigeonVar_replyList[0]! as String,
      message: pigeonVar_replyList[1] as String?,
      details: pigeonVar_replyList[2],
    );
  } else if (pigeonVar_replyList[0] == null) {
    throw PlatformException(
      code: 'null-error',
      message: 'Host platform returned null value for non-null return value.',
    );
  } else {
    return (pigeonVar_replyList[0] as IntMsg?)!;
  }
}