retainAll method
Retains all elements that are present in both this list and other
.
It's time-complexity is O(n²) if other
's contains function is O(n).
[1, 2, 3]..retainAll([1, 2, 4]); // [1, 2]
[1, 2, 3]..retainAll([1, 2, 1]); // [1, 2]
[1, 2, 1]..retainAll([1, 2]); // [1, 2, 1]
Implementation
void retainAll(Iterable<Object?> other) => removeWhere((e) => !other.contains(e));