removeAll method
Removes all elements that are present in both this list and other
.
It's time-complexity is O(n²) if other
's contains method is O(n). When possible, clear should be used instead.
[1, 2, 3]..removeAll([1, 2, 4]); // [3]
Implementation
void removeAll(Iterable<Object?> other) => removeWhere(other.contains);