intersects method

@override @useResult bool intersects(Range<T> other)

Returns true if a non-empty range exists between this and other.

See intersection for computing the intersection of two ranges.

This method is reflexive and symmetric.

Examples

final a = Interval.closed(1, 4);
final b = Interval.closed(1, 4);

a.intersects(b); // true, [1..4] intersects [1..4]

final a = Interval.closed(1, 4);
final b = Interval.closedOpen(2, 3);

a.intersects(b); // true, [1..4] intersects [2..3]

final a = Interval.openClosed(3, 6);
final b = Interval.openClosed(2, 8);

a.intersects(b); // true, (3..6] intersects (4..8]

final a = Interval.openClosed(3, 6);
final b = Interval.closedOpen(1, 2);

a.intersects(b); // false, (3..6] does not intersect (1..2]

final a = Interval.closedOpen(1, 3);
final b = Interval.closedOpen(3, 5);

a.besides(b); // false, [1..3) does not intersect [3..5)

Implementation

@override
@useResult bool intersects(Range<T> other) {
  if (other is Min<T>) {
    return Intersects.minInterval(other, this);

  } else if (other is Max<T>) {
    return Intersects.maxInterval(other, this);

  } else if (other is Interval<T>) {
    return Intersects.intervalInterval(this, other);

  } else {
    return true;
  }
}