springUp method

Future springUp()

Implementation

Future springUp() async {
  if (!isEnabled) return;

  if (_debugLevel > 0) print("springUp-1");

  isSpringDown = false;

  if (hasMultiple) await Future.delayed(const Duration(milliseconds: 500));

  if (_debugLevel > 0) print("springUp-2");

  if (!isSpringDown) animationController.value = 1;
}