spring method

Future spring()

Implementation

Future spring() async {
  if (!isEnabled) return;

  if (_debugLevel > 0) print("spring-1");

  isSpringDown = false;

  if (hasMultiple) await Future.delayed(const Duration(milliseconds: 5));

  if (_debugLevel > 0) print("spring-2");

  if (!isSpringDown) animationController.forward();
}