deserialize static method

num? deserialize(
  1. dynamic value
)

Implementation

static num? deserialize(final dynamic value) {
  if (value == null) {
    return null;
  }

  if (value is num) {
    return value;
  }

  if (value is String) {
    final result = num.tryParse(value);
    return result;
  }

  return null;
}