convertDaysToYearsAndMonths static method

String? convertDaysToYearsAndMonths(int? days)

Function to convert an integer representing days into a string format of years and months.

@param days - The number of days as an integer. @return A string in the format of "X year(s) and Y month(s)".

Implementation

static String? convertDaysToYearsAndMonths(int? days) {
  if (days == null || days < 1) {
    return null;
  }

  // Calculate the number of years by integer division of the days by 365.
  final int years = days ~/ 365;

  // Calculate the remaining number of months by first getting the
  // remainder of days when divided by 365 (which gives the number of
  // days in the current year), then doing integer division by 30.
  final int months = (days % 365) ~/ 30;

  // Determine whether to use singular or plural form for "year" and
  // "month".
  final String yearStr = (years == 1) ? 'year' : 'years';
  final String monthStr = (months == 1) ? 'month' : 'months';

  // Construct the result string.
  if (years > 0 && months > 0) {
    return '$years $yearStr and $months $monthStr';
  } else if (years > 0) {
    return '$years $yearStr';
  } else if (months > 0) {
    return '$months $monthStr';
  } else {
    return '0 days';
  }
}