send<T> method

Future<JsonRpcSuccessResponse<T>> send<T>(
  1. JsonRpcRequest request,
  2. JsonRpcResponseDecoder<Map<String, dynamic>, JsonRpcResponse<T>> decode, {
  3. JsonRpcClientConfig? config,
})

Sends a JSON RPC request to uri and returns its response.

The decode method is used to convert the JSON response to a JsonRpcResponse.

The config object can be used to configure the request.

Implementation

Future<JsonRpcSuccessResponse<T>> send<T>(
  final JsonRpcRequest request,
  final JsonRpcResponseDecoder<Map<String, dynamic>, JsonRpcResponse<T>>
  decode, {
  final JsonRpcClientConfig? config,
}) async {
  final List<int> body = await encoder.convert(request);
  final Map<String, dynamic> json = await handler(
    body,
    config: config,
    id: request.id,
  );
  final JsonRpcResponse<T> response = decode(json);
  return response is JsonRpcErrorResponse<T>
      ? Future.error(response.error) // [JsonRpcException]
      : Future.value(response as JsonRpcSuccessResponse<T>);
}