deserializeList<T> method

  1. @override
List<T>? deserializeList<T>(
  1. List? docs
)
override

Implementation

@override
List<T>? deserializeList<T>(List? docs) => docs != null
    ? List<T>.from(super
        .deserializeList<T>(docs)!
        .map<T>((T obj) => ((obj as FrappeDocument)..doctype = doctype) as T))
    : null;