submitForm method

Future<void> submitForm(
  1. String formId,
  2. Map<String, dynamic> data
)

Submit form from current screen

Implementation

Future<void> submitForm(String formId, Map<String, dynamic> data) async {
  try {
    await backend.submitForm(
      screenId: currentScreenId,
      formId: formId,
      data: data,
    );
    print('Form submitted successfully');
  } on FormSubmissionException catch (e) {
    print('Form submission failed: $e');
  }
}