openLink static method
打开链接或者跳转到其他App @param url 链接
使用示例
void example() {
AppUtil.openLink('https://www.apple.com');
}
Implementation
static void openLink(String url) async {
if (GetUtils.isURL(url)) {
try {
final uri = Uri.parse(url);
if (await canLaunchUrl(uri)) {
await launchUrl(uri);
} else {
throw 'Could not launch $url';
}
} catch (e) {
Logger.log('ppkits openLink error: $e');
}
}
}