toHalfFloat static method
Implementation
static int toHalfFloat(num val) {
// Source: http://gamedev.stackexchange.com/questions/17326/conversion-of-a-number-from-single-precision-floating-point-representation-to-a/17410#17410
/* This method is faster than the OpenEXR implementation (very often
* used, eg. in Ogre), with the additional benefit of rounding, inspired
* by James Tursa?s half-precision code. */
_floatView[0] = val.toDouble();
var x = _int32View[0];
var bits = (x >> 16) & 0x8000; /* Get the sign */
var m = (x >> 12) & 0x07ff; /* Keep one extra bit for rounding */
var e = (x >> 23) & 0xff; /* Using int is faster here */
/* If zero, or denormal, or exponent underflows too much for a denormal
* half, return signed zero. */
if (e < 103) return bits;
/* If NaN, return NaN. If Inf or exponent overflow, return Inf. */
if (e > 142) {
bits |= 0x7c00;
/* If exponent was 0xff and one mantissa bit was set, it means NaN,
* not Inf, so make sure we set one mantissa bit too. */
// bits |= ( ( e == 255 ) ? 0 : 1 ) && ( x & 0x007fffff );
bits |= (e == 255 ? (x & 0x007fffff) : 1);
return bits;
}
/* If exponent underflows but not too much, return a denormal */
if (e < 113) {
m |= 0x0800;
/* Extra rounding may overflow and set mantissa to 0 and exponent
* to 1, which is OK. */
bits |= (m >> (114 - e)) + ((m >> (113 - e)) & 1);
return bits;
}
bits |= ((e - 112) << 10) | (m >> 1);
/* Extra rounding. An overflow will set mantissa to 0 and increment
* the exponent, which is OK. */
bits += m & 1;
return bits;
}