go_to_url function
Implementation
Future<void> go_to_url(String url) async {
final Uri _url = Uri.parse(url);
try {
await launchUrl(_url);
} on PlatformException catch (e) {
logger.e('无法打开 URL,错误信息:$e');
} on UnsupportedError catch (e) {
logger.e('不支持的平台,错误信息:$e');
}
}