e static method
Implementation
static void e(String message, [dynamic error, StackTrace? stackTrace]) {
if (enableLogging) developer.log('ERROR: $message', name: 'OfflineSync', error: error, stackTrace: stackTrace);
}
static void e(String message, [dynamic error, StackTrace? stackTrace]) {
if (enableLogging) developer.log('ERROR: $message', name: 'OfflineSync', error: error, stackTrace: stackTrace);
}