getGroupsWithoutNotice method
获取免打扰的群组列表id
Implementation
Future<List<String>?> getGroupsWithoutNotice() async {
Map result = await _channel
.invokeMethod(EMSDKMethod.getGroupsWithoutPushNotification);
EMError.hasErrorFromResult(result);
var list =
result[EMSDKMethod.getGroupsWithoutPushNotification]?.cast<String>();
return list;
}