showButtonMenu method

void showButtonMenu(Offset triggerPosition)

A method to show a popup menu with the items supplied to ContextMenuButton.itemBuilder at the position of your ContextMenuButton.

By default, it is called when the user taps the button and ContextMenuButton.enabled is set to true. Moreover, you can open the button by calling the method manually.

You would access your ContextMenuButtonState using a GlobalKey and show the menu of the button with globalKey.currentState.showButtonMenu.

Implementation

void showButtonMenu(Offset triggerPosition) {
  final RenderBox button = context.findRenderObject() as RenderBox;
  final RenderBox overlay =
      Overlay.of(context)!.context.findRenderObject() as RenderBox;
  final Rect targetRegion = Rect.fromPoints(
    button.localToGlobal(widget.offset, ancestor: overlay),
    button.localToGlobal(button.size.bottomRight(Offset.zero),
        ancestor: overlay),
  );
  // Only show the menu if there is something to show
  final menu = widget.menu;
  if (menu is RawContextMenu && menu.actions(context).isNotEmpty) {
    return null;
  }

  showContextMenu<T>(
    context: context,
    menu: widget.menu,
    targetRegion: targetRegion,
    triggerPosition: triggerPosition,
    originAligment: widget.originAligment,
    aligment: widget.aligment,
  ).then<void>((T? newValue) {
    if (!mounted) return null;
  });
}