getJob method
Get a job.
Gets a single job. Minimum server version: 4.1 ##### Permissions Must have manage_jobs
permission.
Parameters:
- String jobId (required): Job GUID
Implementation
Future<MmJob?> getJob(
String jobId,
) async {
final response = await getJobWithHttpInfo(
jobId,
);
if (response.statusCode >= HttpStatus.badRequest) {
throw MmApiException(response.statusCode, await _decodeBodyBytes(response));
}
// When a remote server returns no body with a status of 204, we shall not decode it.
// At the time of writing this, `dart:convert` will throw an "Unexpected end of input"
// FormatException when trying to decode an empty string.
if (response.body.isNotEmpty && response.statusCode != HttpStatus.noContent) {
return await apiClient.deserializeAsync(
await _decodeBodyBytes(response),
'MmJob',
) as MmJob;
}
return null;
}