setDifference<T> function

List<T> setDifference<T>(List<T> listA, List<T> listB)

Returns a list of elements that are in listA but not in listB.

The order of elements in the result matches their order in listA.

Example:

setDifference([1, 2, 3], [2, 4]); // => [1, 3]

Implementation

List<T> setDifference<T>(List<T> listA, List<T> listB) {
  final Set<T> setB = Set<T>.from(listB);
  final List<T> difference = [];

  for (final element in listA) {
    if (!setB.contains(element)) {
      difference.add(element);
    }
  }

  return difference;
}