readyCount property

int readyCount
final

How many samples, from the first, were already in the inlet when receivedClock was read. All of them unless coalesce was given.

A sender that pushes chunks delivers their samples together, with time stamps spread over the chunk, so the first sample's is older than its arrival by the time the sender took to fill the chunk. The sample that waited least is the last one that was ready: receivedClock - timestamps[readyCount - 1] is the transit time with no chunking in it, where receivedClock - timestamps.first has the sender's.

Implementation

final int readyCount;