Language.fromJson constructor
Creates this object from a json Map.
Implementation
factory Language.fromJson(Map<String, dynamic> json) => Language(
name: json['name'] as String,
code: json['code'] as String,
longCode: json['longCode'] as String?,
detectedLanguage: json.containsKey('detectedLanguage')
? DetectedLanguage?.fromJson(
json['detectedLanguage'] as Map<String, dynamic>,
)
: null,
);