parseNum static method

num parseNum(
  1. dynamic number
)

字符串转为num类型 number 数据

Implementation

static num parseNum(dynamic number) {
  if (number is num) {
    return number;
  } else if (number is String) {
    return num.parse(number);
  } else {
    throw FormatException('$number is not of type num and String');
  }
}