smoothing method

List<double> smoothing({ int n = 3, })

Smooth this array with n moving averages.

n must be an odd number.

この配列をn個の移動平均で平滑化します。

nは奇数である必要があります。

Implementation

List<double> smoothing({int n = 3}) {
  assert(3 % 2 == 1, "n must be odd number");
  final array = toList();
  final halfN = (n / 2).floor();
  final result = <double>[];
  for (int i = 0; i < array.length; i++) {
    int start = i - halfN;
    int end = i + halfN;
    if (start < 0) {
      start = 0;
    }
    if (end >= array.length) {
      end = array.length - 1;
    }
    double sum = 0;
    for (int j = start; j <= end; j++) {
      sum += array[j];
    }
    result.add(sum / (end - start + 1));
  }
  return result;
}