lastIndexOf method
The last index of element
in this list.
Searches the list backwards from index start
to 0.
The first time an object o
is encountered so that o == element
,
the index of o
is returned.
final notes = <String>['do', 're', 'mi', 're'];
const startIndex = 2;
final index = notes.lastIndexOf('re', startIndex); // 1
If start
is not provided, this method searches from the end of the
list.
final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('re'); // 3
Returns -1 if element
is not found.
final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexOf('fa'); // -1
Implementation
@override
int lastIndexOf(Object? element, [int? start]) {
if (element is! JObject) return -1;
if (start == null || start >= this.length) start = this.length - 1;
if (start == this.length - 1) {
return _lastIndexOfId(
this, const jintType(), [element.reference.pointer]);
}
final range = getRange(start, length);
final res = _lastIndexOfId(
range,
const jintType(),
[element],
);
range.release();
return res;
}