indexOf method

@override int indexOf(Object? element, [ int start = 0 ])

The first index of element in this list.

Searches the list from index start to the end of the list. The first time an object o is encountered so that o == element, the index of o is returned.

final notes = <String>['do', 're', 'mi', 're'];
print(notes.indexOf('re')); // 1

final indexWithStart = notes.indexOf('re', 2); // 3

Returns -1 if element is not found.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.indexOf('fa'); // -1

Implementation

@override
int indexOf(Object? element, [int start = 0]) {
  if (element is! JObject) return -1;
  if (start < 0) start = 0;
  if (start == 0) {
    return _indexOfId(this, const jintType(), [element.reference.pointer]);
  }
  return _indexOfId(
    getRange(start, length),
    const jintType(),
    [element.reference.pointer],
  );
}