pastInput method
Implementation
String pastInput() {
var past = matched.substring(0, (matched.length - match.length));
return (past.length > 20 ? '...' : '') + past.replaceAll('\n', '');
}
String pastInput() {
var past = matched.substring(0, (matched.length - match.length));
return (past.length > 20 ? '...' : '') + past.replaceAll('\n', '');
}