loginIdentifiedUser method

@override Future<void> loginIdentifiedUser({ String? userId, String? email, IntercomStatusCallback? statusCallback, })

Function to create a identified user in Intercom. You need to register your users before you can talk to them and track their activity in your app.

You can register a identified user either with userId or with email, but not with both.

Implementation

@override
Future<void> loginIdentifiedUser({
  String? userId,
  String? email,
  IntercomStatusCallback? statusCallback,
}) async {
  if (userId?.isNotEmpty ?? false) {
    if (email?.isNotEmpty ?? false) {
      throw ArgumentError(
          'The parameter `email` must be null if `userId` is provided.');
    }
    try {
      await _channel.invokeMethod('loginIdentifiedUserWithUserId', {
        'userId': userId,
      });
      statusCallback?.onSuccess?.call();
    } on PlatformException catch (e) {
      statusCallback?.onFailure?.call(_convertExceptionToIntercomError(e));
    }
  } else if (email?.isNotEmpty ?? false) {
    try {
      await _channel.invokeMethod('loginIdentifiedUserWithEmail', {
        'email': email,
      });
      statusCallback?.onSuccess?.call();
    } on PlatformException catch (e) {
      statusCallback?.onFailure?.call(_convertExceptionToIntercomError(e));
    }
  } else {
    throw ArgumentError(
        'An identification method must be provided as a parameter, either `userId` or `email`.');
  }
}