loginWithPassword method

Future<void> loginWithPassword(String userId, String password)

~english Logs in to the chat server with a password.

Param userId The user ID. The maximum length is 64 characters. Ensure that you set this parameter. Supported characters include the 26 English letters (a-z), the ten numbers (0-9), the underscore (_), the hyphen (-), and the English period (.). This parameter is case insensitive, and upper-case letters are automatically changed to low-case ones. If you want to set this parameter as a regular expression, set it as ^a-zA-Z0-9_-+$.

Param password The password. The maximum length is 64 characters. Ensure that you set this parameter.

Throws A description of the exception. See EMError. ~end

~chinese 用户使用密码登录聊天服务器。

Note

Param userId 用户 ID，长度不超过 64 个字符。请确保你对该参数设值。 支持的字符包括英文字母（a-z），数字（0-9），下划线（_），英文横线（-），英文句号（.）。 该参数不区分大小写，大写字母会被自动转为小写字母。如果使用正则表达式设置该参数，则可以将表达式写为：^a-zA-Z0-9_-+$。

Param password 密码，长度不超过 64 个字符。请确保你对该参数设值。

Throws 如果有异常会在这里抛出，包含错误码和错误描述，详见 EMError。 ~end

Implementation

Future<void> loginWithPassword(
  String userId,
  String password,
) async {
  return login(userId, password, true);
}