send method Null safety

  1. @override
Future<StreamedResponse> send(
  1. BaseRequest request
)
override

Sends an HTTP request and asynchronously returns the response.

Implementers should call BaseRequest.finalize to get the body of the request as a ByteStream. They shouldn't make any assumptions about the state of the stream; it could have data written to it asynchronously at a later point, or it could already be closed when it's returned. Any internal HTTP errors should be wrapped as ClientExceptions.

Implementation

@override
Future<StreamedResponse> send(BaseRequest request) async {
  final splitter = StreamSplitter(request.finalize());

  var i = 0;
  for (;;) {
    StreamedResponse? response;
    try {
      response = await _inner.send(_copyRequest(request, splitter.split()));
    } catch (error, stackTrace) {
      if (i == _retries || !_whenError(error, stackTrace)) rethrow;
    }

    if (response != null) {
      if (i == _retries || !_when(response)) return response;

      // Make sure the response stream is listened to so that we don't leave
      // dangling connections.
      _unawaited(response.stream.listen((_) {}).cancel().catchError((_) {}));
    }

    await Future.delayed(_delay(i));
    _onRetry?.call(request, response, i);
    i++;
  }
}