Range

Lazy and efficient 'range' iterables to generate values based on start, stop and step/count.

for (final i in 0.to(5)) {
  print(i);
}

Range a length from [0, n) with step 1:

// int n = 10; // Some length n
for (final i in n.range) {
  print(i);
}

// int n = 10; // Some length n
for (final i in n.take(10)) {
  print(i);
}

Ranges can also be descending:

for (final i in 5.to(-5)) {
  print(i);
}

Linspace

IntRange.linspace returns an Iterable<int> with range start, stop with count elements in it.

print(1.linspace(10, 5));

Time ranges

print(TimeRange(
      DateTime(2019, 1, 1), DateTime(2019, 1, 20), Duration(days: 1)));

Month range

print(MonthRange(DateTime(2020, 2, 29), DateTime(2032, 2, 30), 6));

ticks

print(ticks(-100, 1000000, 10));
// => [-100000, 0, 100000, 200000, 300000, 400000, 500000, 600000, 700000, 800000, 900000]

Extent

Extent of list

print(List.generate(11, (i) => i * 10).findExtent()); // => Extent(0, 100)

Ranging an Extent

print(Extent(5, 50).range(5));

Generate random numbers

print(Extent(5, 50).rands(100));

Extents

Bin

  final extents = List.generate(11, (i) => i * 10).edgesToExtents();
  final data = extents.rands(20)!;
  print(extents.computeBins(data));

Counts

  final extents = List.generate(11, (i) => i * 10).edgesToExtents();
  final data = extents.rands(20)!;
  print(extents.computeCounts(data));

Histogram

  final extents = List.generate(11, (i) => i * 10).edgesToExtents();
  final data = extents.rands(20)!;
  print(extents.computeHistogram(data));