deserialize method

FutureOr<Value>? deserialize(
  1. Serialized serialized, [
  2. Map<String, dynamic> argumentValues = const <String, dynamic>{}
])

Implementation

FutureOr<Value>? deserialize(Serialized serialized,
    [Map<String, dynamic> argumentValues = const <String, dynamic>{}]) {
  if (resolve != null) return resolve!(serialized, argumentValues);
  return type.deserialize(serialized);
}