PhpSettings.fromJson constructor

PhpSettings.fromJson(
  1. Map json_
)

Implementation

PhpSettings.fromJson(core.Map json_)
  : this(
      common:
          json_.containsKey('common')
              ? CommonLanguageSettings.fromJson(
                json_['common'] as core.Map<core.String, core.dynamic>,
              )
              : null,
      libraryPackage: json_['libraryPackage'] as core.String?,
    );