PeopleSuggestion.fromJson constructor

PeopleSuggestion.fromJson(Map json_)

Implementation

PeopleSuggestion.fromJson(core.Map json_)
    : this(
        person: json_.containsKey('person')
            ? Person.fromJson(
                json_['person'] as core.Map<core.String, core.dynamic>)
            : null,
      );