CreateSchemaRegistryRequest.fromJson constructor

CreateSchemaRegistryRequest.fromJson(
  1. Map json_
)

Implementation

CreateSchemaRegistryRequest.fromJson(core.Map json_)
  : this(
      schemaRegistry: json_.containsKey('schemaRegistry')
          ? SchemaRegistry.fromJson(
              json_['schemaRegistry'] as core.Map<core.String, core.dynamic>,
            )
          : null,
      schemaRegistryId: json_['schemaRegistryId'] as core.String?,
    );