Subscription.fromJson constructor

Subscription.fromJson(
  1. Map json_
)

Implementation

Subscription.fromJson(core.Map json_)
  : this(
      archived: json_['archived'] as core.bool?,
      basePlans: (json_['basePlans'] as core.List?)
          ?.map(
            (value) => BasePlan.fromJson(
              value as core.Map<core.String, core.dynamic>,
            ),
          )
          .toList(),
      listings: (json_['listings'] as core.List?)
          ?.map(
            (value) => SubscriptionListing.fromJson(
              value as core.Map<core.String, core.dynamic>,
            ),
          )
          .toList(),
      packageName: json_['packageName'] as core.String?,
      productId: json_['productId'] as core.String?,
      restrictedPaymentCountries:
          json_.containsKey('restrictedPaymentCountries')
          ? RestrictedPaymentCountries.fromJson(
              json_['restrictedPaymentCountries']
                  as core.Map<core.String, core.dynamic>,
            )
          : null,
      taxAndComplianceSettings: json_.containsKey('taxAndComplianceSettings')
          ? SubscriptionTaxAndComplianceSettings.fromJson(
              json_['taxAndComplianceSettings']
                  as core.Map<core.String, core.dynamic>,
            )
          : null,
    );