CreateSchemaRegistryRequest.fromJson constructor

CreateSchemaRegistryRequest.fromJson(
  1. Map json_
)

Implementation

CreateSchemaRegistryRequest.fromJson(core.Map json_)
  : this(
      schemaRegistry:
          json_.containsKey('schemaRegistry')
              ? SchemaRegistry.fromJson(
                json_['schemaRegistry']
                    as core.Map<core.String, core.dynamic>,
              )
              : null,
      schemaRegistryId: json_['schemaRegistryId'] as core.String?,
    );